cupyx.scipy.sparse.linalg.minres#

cupyx.scipy.sparse.linalg.minres(A, b, x0=None, shift=0.0, tol=1e-05, maxiter=None, M=None, callback=None, check=False)[source]#

Uses MINimum RESidual iteration to solve Ax = b.

Parameters:
Returns:

It returns x (cupy.ndarray) and info (int) where x is the converged solution and info provides convergence information.

Return type:

tuple