cupyx.scipy.fft.hfft

cupyx.scipy.fft.hfft(x, n=None, axis=-1, norm=None, overwrite_x=False, *, plan=None)

Compute the FFT of a signal that has Hermitian symmetry.

Parameters
  • a (cupy.ndarray) – Array to be transform.

  • n (None or int) – Length of the transformed axis of the output. For n output points, n//2+1 input points are necessary. If n is not given, it is determined from the length of the input along the axis specified by axis.

  • axis (int) – Axis over which to compute the FFT.

  • norm (None or "ortho") – Keyword to specify the normalization mode.

  • overwrite_x (bool) – If True, the contents of x can be destroyed.

  • plan (None) – This argument is currently not supported.

Returns

The transformed array which shape is specified by n and type will convert to complex if the input is other. If n is not given, the length of the transformed axis is 2*(m-1) where m is the length of the transformed axis of the input.

Return type

cupy.ndarray

See also

scipy.fft.hfft()